ELECTRICAL
NOTES
Heat produced by 1 kg Atomic material is
equivalent to 2700 quintal coal.
In India: AC supply is 33Kv, 66Kv, 132Kv,220Kv, 400Kv
:
DC supply is 100Kv, 200Kv, 300Kv, 400Kv, 600Kv 800Kv.
Difference between Overhead line & underground
line.
sn
|
Overhead line
|
Underground line
|
1
|
Cheap to install
|
Costly to install
|
2
|
Easy disconnection
|
Disconnection is not
possible
|
3
|
When load increases, extra
connection is to be given & connections can be changed.
|
Not possible
|
4
|
Line voltage can be
increased
|
For increasing line
voltage, cable to be replaced
|
5
|
In emergency excess load
can be given
|
Possibility of cable break
|
6
|
Fault can be easily
detected
|
Hard to detect the fault
|
Dielectric Strength: The point on which voltage can stand.
1.
Material
thickness, 2. Temperature, 3. Size of electrode, moisture absorbent value.
1.
Air –
3.2 Kv/mm
2.
– 12 to 20Kv/mm
3.
Mica_
20 to 60 Kv/mm
4.
Porcelene
– 15 to 60 Kv/mm
5.
Trx
oil – 20 kv/mm – 50 kv/2.5mm (IS 335)
Ø Tungsten is used as a filament of lamp because the temperature
coefficient of tungsten is high and melting point is also high.
Ø Vacuum is a media in the lamp because filament
should not burn.
Ø Gas is filled in the lamp to increase the
capacity of the lamp. Gas: ozone, Helium
etc(inert gasses)
Type of lamps and advantages:
1.
Fluorescent
lamp: Household use & internal light of the bldg.
2.
Incandescent
lamp: Household use & internal light of the bldg.
3.
Mercury
vapor Lamp: Road & ground
4.
Sodium
vapor lamp: Road & ground
5.
Neon
lamp: Advertisement
6.
Arc
lamp: Search light & cinema projector
ü To remove motor bearing permanently – use
puller
ü To fix motor bearing: Bearing to be heated
up to 800C & then it can be fixed easily
ü Roller
bearing is mostly provided
to driving end side.
ü Ball
bearing can be provided to
both the ends or non-driving end.
ü Fuse
is used in place of
neutral link: If there is unbalance load, current will flow through fuse and it
will blow and series ckt will form. Then low voltage will flow from excess load
side & high voltage from lesser load side. 2 phase supply will flow if it
is single phase and equipment will burn.
ü 3
ph loads should be balanced
because in the balance load, current is same in each phase. If there is
unbalance load, current will also unbalance. So there is a change to damage the
equipment. Sometimes in the balance load, current flowing through neutral is
zero. In the unbalance load, current flows through neutral & the phase on
which load is excess, voltage will low and equipment will not work properly. If
load of the phase is less, voltage will more and the equipments can get
damaged. So balancing of load is necessary.
ü Auto
transformer starter is
used in place of star delta starter to increase Starting torque as in starting,
80% voltage is getting to winding
ü Star delta starter gives less starting
torque because in starting 58% voltage is getting to winding.
ü If
motor trips while starting by star-delta starter, timer setting may low. Timer to be set on 80% speed
of the motor.
ü For
heavy torque, DOL starter
is used. 100% voltage is getting to the winding.
ü Inductance: If supply is given to a coil,
which opposes to the voltage is inductance.
ü Impedance: Ckt consist of resistance,
Inductance & capacitance, the total resistance is called impedance. Its
unit is Ωmho. Z= √R2+(XL-XC)2.
ü Resistance = V x I
ü Inductance = L = XL/2πF
ü Capacitance = 1/2πFXC
ü Capacitive reactance Xc = 1/2πFXC
ü Inductive reactance XL = 2πFXL
ü Capacitor50 mfd & 100 mfd =100 mfd Capacitor
will take more current
ü PF depend upon inductive reactance &
capacitive reactance.
ü PF on load: Resistive ckt – Unity
: Inductive ckt – Lagging
: Capacitive ckt- Leading
ü No
volt coil is connected in
the series of field coil.
ü Over load coil is connected in the series
of supply and load
ü 3ph, 10HP motor installation: It will take
mostly 15 amps current.
i.
3½
core, 2.5sq mm Al conductor, PVC insulated armored cable
ii.
32
Amps switch-fuse unit or isolator
iii.
16 swg
copper conductor for earthing
iv.
Over
load relay: 10 – 25Amps.
v.
Back
up fuse: 35Amps HRC (2.5 times of full load current)
vi.
Indication
lamps On Off, 3 ph, trip : 6 Nos.
vii.
Ammeter
& voltmeter selector switches
viii.
Motor
insulation resistance
ix.
Cable
insulation resistance
Output
ü Efficiency
of motor= --------- x 100%
Input
Out put
KWH
ü All
day efficiency = ------------------- X 100%
Input KWH
No load
Voltage – Load Voltage
ü Voltage
Regulation = -------------------------------------------
No load Voltage
ü If the Gap between Stator & Rotor of
induction motor is minimum, magnetizing current will less and power factor will
increase.
Torque = Ir x Cos Φ = Rotor current x Rotor
pf.
ü Fault
level : Switch yard – 1000
MVA
33 Kv busbar- 750 MVA
3.3 Kv busbar- 175 MVA
MV busbar - 35 MVA
ü Neutral
displacement: On Earth
fault, lightening, voltage increases. This increased voltage is controlled.
ü Lightening
arrestor: On system
voltage it works as a insulator & on high voltage it works as conductor.
ü Direct
stroke: By direct earth
wire, in earth or ground – 80% negative, 20% positive charge.
ü Non
direct stroke: Drop in
overhead line & observe arrestor & goes to ground: -ve + positive.
ü If
DC supply is given to transformer, it will burn because there will no induction and it will become a
resistive ckt and will take high current and will burnt transformer winding.
ü DG
AVR Fails: It means
failure of excitation, hence DG will be continue running but no EMF will be
generator.
ü
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